Printing intermediate Integers between one element & next element of array

Problem : Printing intermediate Integers

User entered numbers are set into array.Intermediate integer of each pair of successive elements to be printed.

Input :
Input of 1st line is number of element in array,inputs of 2nd line are array elements.
Output :
Output of each line is intermediate integers between each two succesive array element.
Example :

Input	Output
3 2 6 8 3	3 4 5 7 4 5 6 7
3 8 8 9	"no  intermediate element in between these 8 & 9 elements" "no  intermediate element in between these 9 & 9 elements"

 Solution : 

Logic for Printing intermediate Integers 

1. Entered numbers kept stored in array                             
2. For loop executes for each pair of successive array elements.
i) If two successive array elements are same or difference between two successive array elements is one ,then no intermediate integer presence message is printed . 
ii) Lesser number is identified in between two numbers of each pair.
iii) printing starts from the number one more than lesser number ,this number incremented by one,again printed,this continues upto the number one less than grater number between pair.

Code : 

#include"iostream";
using namespace std;
main()
{
 int n;
 cout<<"Enter number of Integer in array "<<endl;
 cin>>n;
 int num[n];
 cout<<"Enter elements of array "<<endl;
 for(int p=0;p<n;p++)
 cin>>num[p];
 for(int k=0;k<n-1;k++)
 {
   if((num[k]-num[k+1]==1) || (num[k+1]-num[k]==1) || (num[k]==num[k+1]))
   {
   cout<<"No intermediate element in between these "<<num[k]<<" & "<<num[k+1]<<" elements "<<endl;
   }
   else if(num[k]<num[k+1])
   {
     cout<<"Element between "<<num[k]<<" and "<<num[k+1]<<" is/are ";
     for(int a=num[k];a<num[k+1]-1;)
     {
        cout<<++a<<" ";   //printing intermediate element 
     }
     cout<<endl;
   }
   else if(num[k]>num[k+1])
   {
     cout<<"Element between "<<num[k]<<" and "<<num[k+1]<<" is/are ";
     for(int a=num[k+1];a<num[k]-1;)
       {
         cout<<++a<<" ";   //printing intermediate element
       }
       cout<<endl;
    }
  }
}

Click here to see running code on Ideone with input 4 2 6 8 3

Click here to see running code on Ideone with input 3 8 9 9

Explanation : 

Entered 1st input set’s numbers are stored in array ‘num’ like below –

First (2,6) ,then (6,8),then (8,3) pair get considered.Intermediate values are printed.
Entered 2nd input set’s numbers are stored in array ‘num’ like below –

First (8,9) ,then (9,9) pair get considered.No intermediate element present message is printed.

Another Logic and Code : 

#include"iostream";
using namespace std;
main()
{
int n,a,b,large,small;
cout<<"Enter number of Integer in array "<<endl;
cin>>n;
int num[n];
cout<<"Enter element of array "<<endl;
for(int p=0;p<n;p++)
cin>>num[p];
for(int k=0;k<n-1;k++)
{
 a=num[k];
 b=num[k+1];
 if((num[k]-num[k+1]==1) || (num[k+1]-num[k]==1) || (num[k]==num[k+1]))
 {
 cout<<"No intermediate element present in between these "<<num[k]<<" & "<<num[k+1]<<" elements";
 }
else
{
large=a>b?a:b;   //identifying larger number of pair 
small=a<b?a:b;   //identifying smaller number of pair
cout<<"Element between "<<num[k]<<" and "<<num[k+1]<<" is/are ";
for(int p=small;p<large-1;)
{
 cout<<++p<<" ";   //printing intermediate element
}
}
cout<<endl;
}
}

Click here to see running code on Ideone with input 4 2 6 8 3
Click here to see running code on Ideone with input 3 8 9 9

Explanation : 

If two successive array elements are same or difference between two successive array elements is one ,then no intermediate integer presence message is printed .Larger & smaller number in pair are identified by ternary operator ,then printing starts from the number one more than small ,continues upto the number one less than larger .