• Skip to primary navigation
  • Skip to content
  • Skip to primary sidebar
  • Skip to secondary sidebar

GoHired

Interview Questions asked in Google, Microsoft, Amazon

Join WeekEnd Online Batch from 4-April-2020 on How to Crack Coding Interview in Just 10 Weeks : Fees just 20,000 INR

  • Home
  • Best Java Books
  • Algorithm
  • Internship
  • Certificates
  • About Us
  • Contact Us
  • Privacy Policy
  • Array
  • Stack
  • Queue
  • LinkedList
  • DP
  • Strings
  • Tree
  • Mathametical
  • Puzzles
  • Graph

BFS (Breath First Search)

March 1, 2014 by Dhaval Dave

In graph theory, breadth-first search (BFS) is a strategy for searching in a graph when search is limited to essentially two operations: (a) visit and inspect a node of a graph; (b) gain access to visit the nodes that neighbor the currently visited node. The BFS begins at a root node and inspects all the neighboring nodes. Then for each of those neighbor nodes in turn, it inspects their neighbor nodes which were unvisited, and so on. Compare BFS with the equivalent, but more memory-efficient Iterative deepening depth-first search and contrast with depth-first search.

Algorithm

The algorithm uses a queue data structure to store intermediate results as it traverses the graph, as follows:

1) Enqueue the root node
2) Dequeue a node and examine it

  • If the element sought is found in this node, quit the search and return a result.
  • Otherwise enqueue any successors (the direct child nodes) that have not yet been discovered.

3)If the queue is empty, every node on the graph has been examined – quit the search and return “not found”. 4)If the queue is not empty, repeat from Step 2.

C program

#include<stdio.h>
#include<conio.h>
int a[20][20],q[20],visited[20],n,i,j,f=0,r=-1;
void bfs(int v)
{
 for(i=1;i<=n;i++)
  if(a[v][i] && !visited[i])
   q[++r]=i;
 if(f<=r)
 {
  visited[q[f]]=1;
  bfs(q[f++]);
 }
}
void main()
{
 int v;
 clrscr();
 printf("n Enter the number of vertices:");
 scanf("%d",&n);
 for(i=1;i<=n;i++)
 {
  q[i]=0;
  visited[i]=0;
 }
 printf("n Enter graph data in matrix form:n");
 for(i=1;i<=n;i++)
  for(j=1;j<=n;j++)
   scanf("%d",&a[i][j]);
 printf("n Enter the starting vertex:");
 scanf("%d",&v);
 bfs(v);
 printf("n The node which are reachable are:n");
 for(i=1;i<=n;i++)
  if(visited[i])
   printf("%dt",i);
  else
   printf("n Bfs is not possible");
 getch();
}

Similar Articles

Filed Under: problem Tagged With: Binary Tree, Graph, tree

Reader Interactions

Primary Sidebar

Join WeekEnd Online/Offline Batch from 4-April-2020 on How to Crack Coding Interview in Just 10 Weeks : Fees just 20,000 INR

Join WeekEnd Online/Offline Batch from 4-April-2020

WhatsApp us

Secondary Sidebar

Custom Search

  • How I cracked AMAZON
  • LeetCode
  • Adobe
  • Amazon
  • Facebook
  • Microsoft
  • Hacker Earth
  • CSE Interview

Top Rated Questions

CodeChef Code SGARDEN

Mirror of Tree

How Radix sort works

Find Percentage of Words matching in Two Strings

Cisco Hiring Event 21st – 22nd Feb 2015

SAP Off Campus Hiring_ March 2015 Computer Skills

Length of the longest substring without repeating characters

Doubly linked list

Binary Tree Isomorphic to each other

Circular Linked List

write a c program that given a set a of n numbers and another number x determines whether or not there exist two elements in s whose sum is exactly x

Closed Parentheses checker

The greedy coins game Dynamic Programming

LeetCode: Binary Tree Maximum Path Sum

DFS (Depth First Search)

Test Cases for Round Function

C++ OOPs Part2

SAP Hiring Off-Campus General Aptitude

Leetcode: Edit Distance

Inorder and Preorder traversals of a Binary Tree given. Output the Postorder traversal of it.

Longest Increasing Subsequence

CodeChef’ RRCOPY

Find min element in Sorted Rotated Array (With Duplicates)

HackeEarth Flipkart’s Drone

Find two non repeating elements in an array of repeating elements

The Magic HackerEarth Nirvana solutions Hiring Challenge

Stickler thief

Binary Tree in Java

There are N nuts and N bolts, u have to find all the pairs of nuts and bolts in minimum no. of iteration

Generate largest number arranging a no. of given non negative integer numbers

Copyright © 2026 · Genesis Framework · WordPress · Log in