### Printing Longest Common Subsequence

Given two sequences, print the longest subsequence present in both of them.

Examples:

LCS for input Sequences “ABCDGH” and “AEDFHR” is “ADH” of length 3.

LCS for input Sequences “AGGTAB” and “GXTXAYB” is “GTAB” of length 4.

We have discussed Longest Common Subsequence (LCS) problem in a previous post. The function discussed there was mainly to find the length of LCS. To find length of LCS, a 2D table L[][] was constructed. In this post, the function to construct and print LCS is discussed.

/* Dynamic Programming implementation of LCS problem */ #include<iostream> #include<cstring> #include<cstdlib> using namespace std; /* Returns length of LCS for X[0..m-1], Y[0..n-1] */ void lcs( char *X, char *Y, int m, int n ) { int L[m+1][n+1]; /* Following steps build L[m+1][n+1] in bottom up fashion. Note that L[i][j] contains length of LCS of X[0..i-1] and Y[0..j-1] */ for (int i=0; i<=m; i++) { for (int j=0; j<=n; j++) { if (i == 0 || j == 0) L[i][j] = 0; else if (X[i-1] == Y[j-1]) L[i][j] = L[i-1][j-1] + 1; else L[i][j] = max(L[i-1][j], L[i][j-1]); } } // Following code is used to print LCS int index = L[m][n]; // Create a character array to store the lcs string char lcs[index+1]; lcs[index] = ''; // Set the terminating character // Start from the right-most-bottom-most corner and // one by one store characters in lcs[] int i = m, j = n; while (i > 0 && j > 0) { // If current character in X[] and Y are same, then // current character is part of LCS if (X[i-1] == Y[j-1]) { lcs[index-1] = X[i-1]; // Put current character in result i--; j--; index--; // reduce values of i, j and index } // If not same, then find the larger of two and // go in the direction of larger value else if (L[i-1][j] > L[i][j-1]) i--; else j--; } // Print the lcs cout << "LCS of " << X << " and " << Y << " is " << lcs; } /* Driver program to test above function */ int main() { char X[] = "AGGTAB"; char Y[] = "GXTXAYB"; int m = strlen(X); int n = strlen(Y); lcs(X, Y, m, n); return 0; }

-IF YOU LIKE OUR EFFORT, PLEASE LIKE AND SHARE OUR FB-PAGE AND SITE