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Trie Dictionary

April 14, 2015 by Dhaval Dave

Trie also called prefix tree (as they can be searched by prefixes).
The term trie comes from retrieval.
In the example shown, keys are listed in the nodes and values below them. Each complete English word has an arbitrary integer value associated with it.
A trie can be seen as a deterministic finite automaton without loops. Each finite language is generated by a trie automaton, and each trie can be compressed into a DAFSA.
It is not necessary for keys to be explicitly stored in nodes. (In the figure, words are shown only to illustrate how the trie works.)

tries
tries
struct trie_node
{
 int value; /* Used to mark leaf nodes */
 trie_node_t *children[ALPHABET_SIZE];
};

Code

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
 
#define ARRAY_SIZE(a) sizeof(a)/sizeof(a[0])
 
// Alphabet size (# of symbols)
#define ALPHABET_SIZE (26)
// Converts key current character into index
// use only 'a' through 'z' and lower case
#define CHAR_TO_INDEX(c) ((int)c - (int)'a')
 
// trie node
typedef struct trie_node trie_node_t;
struct trie_node
{
 int value;
 trie_node_t *children[ALPHABET_SIZE];
};
 
// trie ADT
typedef struct trie trie_t;
struct trie
{
 trie_node_t *root;
 int count;
};
 
// Returns new trie node (initialized to NULLs)
trie_node_t *getNode(void)
{
 trie_node_t *pNode = NULL;
 
 pNode = (trie_node_t *)malloc(sizeof(trie_node_t));
 
 if( pNode )
 {
 int i;
 
 pNode->value = 0;
 
 for(i = 0; i < ALPHABET_SIZE; i++)
 {
 pNode->children[i] = NULL;
 }
 }
 
 return pNode;
}
 
// Initializes trie (root is dummy node)
void initialize(trie_t *pTrie)
{
 pTrie->root = getNode();
 pTrie->count = 0;
}
 
// If not present, inserts key into trie
// If the key is prefix of trie node, just marks leaf node
void insert(trie_t *pTrie, char key[])
{
 int level;
 int length = strlen(key);
 int index;
 trie_node_t *pCrawl;
 
 pTrie->count++;
 pCrawl = pTrie->root;
 
 for( level = 0; level < length; level++ )
 {
 index = CHAR_TO_INDEX(key[level]);
 if( !pCrawl->children[index] )
 {
 pCrawl->children[index] = getNode();
 }
 
 pCrawl = pCrawl->children[index];
 }
 
 // mark last node as leaf
 pCrawl->value = pTrie->count;
}
 
// Returns non zero, if key presents in trie
int search(trie_t *pTrie, char key[])
{
 int level;
 int length = strlen(key);
 int index;
 trie_node_t *pCrawl;
 
 pCrawl = pTrie->root;
 
 for( level = 0; level < length; level++ )
 {
 index = CHAR_TO_INDEX(key[level]);
 
 if( !pCrawl->children[index] )
 {
 return 0;
 }
 
 pCrawl = pCrawl->children[index];
 }
 
 return (0 != pCrawl && pCrawl->value);
}
 
// Driver
int main()
{
 // Input keys (use only 'a' through 'z' and lower case)
 char keys[][8] = {"the", "a", "there", "answer", "any", "by", "bye", "their"};
 trie_t trie;
 
 char output[][32] = {"Not present in trie", "Present in trie"};
 
 initialize(&trie);
 
 // Construct trie
 for(int i = 0; i < ARRAY_SIZE(keys); i++)
 {
 insert(&trie, keys[i]);
 }
 
 // Search for different keys
 printf("%s --- %s\n", "the", output[search(&trie, "the")] );
 printf("%s --- %s\n", "these", output[search(&trie, "these")] );
 printf("%s --- %s\n", "their", output[search(&trie, "their")] );
 printf("%s --- %s\n", "thaw", output[search(&trie, "thaw")] );
 
 return 0;
}

code courtesy : geeksforgeeks.org & Venki

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Filed Under: Amazon Interview Question, Interview Questions, Microsoft Interview Questions, problem Tagged With: tree, Trie

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