• Skip to primary navigation
  • Skip to content
  • Skip to primary sidebar
  • Skip to secondary sidebar

GoHired

Interview Questions asked in Google, Microsoft, Amazon

Join WeekEnd Online Batch from 4-April-2020 on How to Crack Coding Interview in Just 10 Weeks : Fees just 20,000 INR

  • Home
  • Best Java Books
  • Algorithm
  • Internship
  • Certificates
  • About Us
  • Contact Us
  • Privacy Policy
  • Array
  • Stack
  • Queue
  • LinkedList
  • DP
  • Strings
  • Tree
  • Mathametical
  • Puzzles
  • Graph

Binary Tree in Java

April 9, 2015 by Dhaval Dave

How to write Binary Search Tree Code in Java with proper class structure and methods.

Here is the implementation of Binary Search Tree in Java.
Class Structure, Get Set Methods, Binary Tree Operation, Pre-Post-InOrder code and Testing Function is written Step by Step

ADT/Class Structure for Tree in java

Also Check this Best Books on Java 

class BinaryNode{
 private int Data;
 private Object Data;
 private BinaryNode Left;
 private BinaryNode Right;

 public BinaryNode(){ 
 Key = gio.ReadInteger("Enter in Key Value: ");
 Data = gio.ReadString("Enter in data : ");
 Left = null;
 Right = null;
 }
public class BTree
    {
    private BinaryNode Root;
    private int NoOfNodes;

    private BTree(){                                    
      Root = null;
      NoOfNodes = 0;
     }

Get Methods

public int gKey()
    {
    return Key;
    }

  public Object gData()
    {
    return Data;
    }

  public BinaryNode gLeft()
    {
    return Left;
    }
  public BinaryNode gRight()
    {
    return Right;
    }

Set Methods

public void sKey(int AValue)
    {
    Key = AValue;
    }

  public void sData(Object AValue)
    {
    Data = AValue;
    }

  public void sLeft( BinaryNode AValue)
    {
    Left = AValue;
    }

  public void sRight( BinaryNode AValue)
    {
    Right = AValue;
    }
}

Binary Tree Operations

public boolean IsEmpty(){
      return(NoOfNodes == 0);
      }
public BinaryNode gRoot()    {
      return Root; 
}
public int Count() { 
   return NoOfNodes; 
}
public int Size(BinaryNode ATree){
 if (ATree == null)
 return 0;
 else
 return(1 + Size(ATree.gLeft()) + Size(ATree.gRight()));
 }
public int Height(BinaryNode ATree){
 if (ATree == null)
 return 0;
 else
 return (1 + Math.max(Height(ATree.gLeft()), Height(ATree.gRight())));
 }

PreOrder PostOrder InOrder

public void PreOrder(BinaryNode ATree){
      if (ATree != null){
        System.out.println(ATree.gData());
        PreOrder(ATree.gLeft());
        PreOrder(ATree.gRight());
        }
      }

    public void InOrder(BinaryNode ATree){
      if (ATree != null){
        InOrder(ATree.gLeft());
        System.out.println(ATree.gData());
        InOrder(ATree.gRight());
        }
      }

public void PostOrder(BinaryNode ATree){
      if (ATree != null){
        PostOrder(ATree.gLeft());
        PostOrder(ATree.gRight());
        System.out.println(ATree.gData());
        }
      }

Insert Operation

public void Insert(int AId, Object AValue){ 
//For Binary Searh Tree //
      BinaryNode Temp,Current,Parent;
      if(Root == null){
        Temp = new BinaryNode(AId,AValue);
        Root = Temp;
        NoOfNodes++;
        }
      else {
        Temp = new BinaryNode(AId,AValue);
        Current = Root;
        while(true){
          Parent = Current;
          if(AId < Current.gKey())
            {
            Current = Current.gLeft();
              if (Current == null)
                {
                Parent.sLeft(Temp);
                NoOfNodes++;
                return;
                }
            }
          else
            {
            Current = Current.gRight();
            if(Current == null)
              {
              Parent.sRight(Temp);
              NoOfNodes++;
              return;
              }
            }
          }
        }

Search

public BinaryNode Find(int AKey)
      {
      BinaryNode Current = null;
      if(!IsEmpty())
        {
        Current = Root; 
        while(Current.gKey() != AKey)
          {
          if(AKey < Current.gKey())
            Current = Current.gLeft();
          else
            Current = Current.gRight();
          if(Current == null)
            return null;
          }
        }
        return Current;
      }

Main Method

public static void main (String [] Args)
    { 
    BTree MyTree = new BTree();                
    BinaryNode NodeAt;                           
    //Insert data into the tree - key and some text
    MyTree.Insert(12,"Hen");
    MyTree.Insert(4,"Dog");
    MyTree.Insert(11,"Cat");
    MyTree.Insert(1,"Frog");
    MyTree.Insert(100,"Owner");
    MyTree.Delete(1);
    MyTree.InOrder(MyTree.gRoot());       
    NodeAt = MyTree.Find(11);

    if(NodeAt !=null)
      System.out.println("Data in Node with Key 11 = " + NodeAt.gData());
    System.exit(0);
    }//end of test code
  }// end of class code

Similar Articles

Filed Under: Interview Questions, problem Tagged With: Java

Reader Interactions

Primary Sidebar

Join WeekEnd Online/Offline Batch from 4-April-2020 on How to Crack Coding Interview in Just 10 Weeks : Fees just 20,000 INR

Join WeekEnd Online/Offline Batch from 4-April-2020

WhatsApp us

Secondary Sidebar

Custom Search

  • How I cracked AMAZON
  • LeetCode
  • Adobe
  • Amazon
  • Facebook
  • Microsoft
  • Hacker Earth
  • CSE Interview

Top Rated Questions

Sort an array according to the order defined by another array

Skiing on Mountains Matrix

Subset Sum Problem Dynamic programming

The Magic HackerEarth Nirvana solutions Hiring Challenge

Minimum insertions to form a palindrome

1014 Practice Question of New GRE – Princeton

Spanning Tree

LeetCode : Word Search

Printing Longest Common Subsequence

Stickler thief

Microsoft BING Interview Experience

K’th Largest Element in BST when modification to BST is not allowed

Memory Efficient LinkedList

Wrong Directions given find minimum moves so that he can reach to the destination

TicTacToe Game As Asked in Flipkart

Add Sub Multiply very large number stored as string

Difference between a LinkedList and a Binary Search Tree BST

Max Sum in circularly situated Values

Trapping Rain Water

‘N’ Story Building, with 1,2,3 steps how many ways can a person reach top of building.

Closed Parentheses checker

Handle duplicates in Binary Search Tree

C++ OOPs Part1

Apriori algorithm C Code Data Mining

Linked List V/S Binary Search Tree

Print vertical sum of all the axis in the given binary tree

SAP Off Campus Hiring_ March 2015 Analytical Aptitude

Python List

Right view of Binary tree

Amazon Interview Experience – SDE Chennai

Copyright © 2025 · Genesis Framework · WordPress · Log in